Fix lycanthropy tutorial

"lycanthropy" was consistently misspelled, and the tutorial was mixed between requiring "exactly 2" for the attribute in the code, while being described as "greater than 2" in some of the text, and the attribute was actually set to 3, preventing the example code from working.

docs/source/Howtos/Beginner-Tutorial/Part1/Beginner-Tutorial-Django-queries.md

@@ -14,7 +14,7 @@ But sometimes you need to be more specific:
 
 - You want to find all `Characters` ...
 - ... who are in Rooms tagged as `moonlit` ...
-- ... _and_ who has the Attribute `lycantrophy` with a level higher than 2 ...
+- ... _and_ who has the Attribute `lycanthropy` with a level equal to 2 ...
 - ... because they should immediately transform to werewolves!
 
 In principle you could achieve this with the existing search functions combined with a lot of loops
@@ -159,7 +159,7 @@ of this lesson.
 Firstly, we make ourselves and our current location match the criteria, so we can test:
 
     > py here.tags.add("moonlit")
-    > py me.db.lycantrophy = 3
+    > py me.db.lycanthropy = 2
 
 This is an example of a more complex query. We'll consider it an example of what is
 possible.
@@ -174,7 +174,7 @@ will_transform = (
     Character.objects
     .filter(
         db_location__db_tags__db_key__iexact="moonlit",
-        db_attributes__db_key="lycantrophy",
+        db_attributes__db_key="lycanthropy",
         db_attributes__db_value__eq=2
     )
 )
@@ -189,7 +189,7 @@ Don't confuse database fields with [Attributes](../../../Components/Attributes.m
 	    - ... and on that location, we get the value of `db_tags` (this is a _many-to-many_ database field
         that we can treat like an object for this purpose; it references all Tags on the location)
 	    - ... and from those `Tags`, we looking for `Tags` whose `db_key` is "monlit" (non-case sensitive).
-     - **Line 7**: ... We also want only Characters with `Attributes` whose `db_key` is exactly `"lycantrophy"`
+     - **Line 7**: ... We also want only Characters with `Attributes` whose `db_key` is exactly `"lycanthropy"`
     - **Line 8** :... at the same time as the `Attribute`'s `db_value` is exactly 2.
 
 Running this query makes our newly lycantrophic Character appear in `will_transform` so we know to transform it. Success!
@@ -228,7 +228,7 @@ works like `NOT`.
 Would get all Characters that are either named "Dalton" _or_ which is _not_ in prison. The result is a mix
 of Daltons and non-prisoners.
 
-Let us expand our original werewolf query. Not only do we want to find all Characters in a moonlit room with a certain level of `lycanthrophy` - we decide that if they have been _newly bitten_, they should also turn, _regardless_ of their lycantrophy level (more dramatic that way!).
+Let us expand our original werewolf query. Not only do we want to find all Characters in a moonlit room with a certain level of `lycanthrophy` - we decide that if they have been _newly bitten_, they should also turn, _regardless_ of their lycanthropy level (more dramatic that way!).
 
 Let's say that getting bitten means that you'll get assigned a Tag `recently_bitten`.
 
@@ -242,7 +242,7 @@ will_transform = (
     .filter(
         Q(db_location__db_tags__db_key__iexact="moonlit")
         & (
-          Q(db_attributes__db_key="lycantrophy",
+          Q(db_attributes__db_key="lycanthropy",
             db_attributes__db_value__eq=2)
           | Q(db_tags__db_key__iexact="recently_bitten")
         ))
@@ -256,7 +256,7 @@ That's quite compact. It may be easier to see what's going on if written this wa
 from django.db.models import Q
 
 q_moonlit = Q(db_location__db_tags__db_key__iexact="moonlit")
-q_lycantropic = Q(db_attributes__db_key="lycantrophy", db_attributes__db_value__eq=2)
+q_lycantropic = Q(db_attributes__db_key="lycanthropy", db_attributes__db_value__eq=2)
 q_recently_bitten = Q(db_tags__db_key__iexact="recently_bitten")
 
 will_transform = (
@@ -276,7 +276,7 @@ the same object with different relations.
 ```
 
 This reads as "Find all Characters in a moonlit room that either has the
-Attribute `lycantrophy` higher than two, _or_ which has the Tag
+Attribute `lycanthropy` equal to two, _or_ which has the Tag
 `recently_bitten`". With an OR-query like this it's possible to find the same
 Character via different paths, so we add `.distinct()` at the end. This makes
 sure that there is only one instance of each Character in the result.
@@ -406,4 +406,4 @@ in a format like the following:
 
 ## Conclusions
 
-We have covered a lot of ground in this lesson and covered several more complex topics. Knowing how to query using Django is a powerful skill to have. 
+We have covered a lot of ground in this lesson and covered several more complex topics. Knowing how to query using Django is a powerful skill to have.