diff --git a/docs/source/Howtos/Beginner-Tutorial/Part1/Beginner-Tutorial-Django-queries.md b/docs/source/Howtos/Beginner-Tutorial/Part1/Beginner-Tutorial-Django-queries.md
index d13c631cc8..a34d63e01d 100644
--- a/docs/source/Howtos/Beginner-Tutorial/Part1/Beginner-Tutorial-Django-queries.md
+++ b/docs/source/Howtos/Beginner-Tutorial/Part1/Beginner-Tutorial-Django-queries.md
@@ -14,7 +14,7 @@ But sometimes you need to be more specific:
 
 - You want to find all `Characters` ...
 - ... who are in Rooms tagged as `moonlit` ...
-- ... _and_ who has the Attribute `lycantrophy` with a level higher than 2 ...
+- ... _and_ who has the Attribute `lycanthropy` with a level equal to 2 ...
 - ... because they should immediately transform to werewolves!
 
 In principle you could achieve this with the existing search functions combined with a lot of loops
@@ -159,7 +159,7 @@ of this lesson.
 Firstly, we make ourselves and our current location match the criteria, so we can test:
 
     > py here.tags.add("moonlit")
-    > py me.db.lycantrophy = 3
+    > py me.db.lycanthropy = 2
 
 This is an example of a more complex query. We'll consider it an example of what is
 possible.
@@ -174,7 +174,7 @@ will_transform = (
     Character.objects
     .filter(
         db_location__db_tags__db_key__iexact="moonlit",
-        db_attributes__db_key="lycantrophy",
+        db_attributes__db_key="lycanthropy",
         db_attributes__db_value__eq=2
     )
 )
@@ -189,7 +189,7 @@ Don't confuse database fields with [Attributes](../../../Components/Attributes.m
 	    - ... and on that location, we get the value of `db_tags` (this is a _many-to-many_ database field
         that we can treat like an object for this purpose; it references all Tags on the location)
 	    - ... and from those `Tags`, we looking for `Tags` whose `db_key` is "monlit" (non-case sensitive).
-     - **Line 7**: ... We also want only Characters with `Attributes` whose `db_key` is exactly `"lycantrophy"`
+     - **Line 7**: ... We also want only Characters with `Attributes` whose `db_key` is exactly `"lycanthropy"`
     - **Line 8** :... at the same time as the `Attribute`'s `db_value` is exactly 2.
 
 Running this query makes our newly lycantrophic Character appear in `will_transform` so we know to transform it. Success!
@@ -228,7 +228,7 @@ works like `NOT`.
 Would get all Characters that are either named "Dalton" _or_ which is _not_ in prison. The result is a mix
 of Daltons and non-prisoners.
 
-Let us expand our original werewolf query. Not only do we want to find all Characters in a moonlit room with a certain level of `lycanthrophy` - we decide that if they have been _newly bitten_, they should also turn, _regardless_ of their lycantrophy level (more dramatic that way!).
+Let us expand our original werewolf query. Not only do we want to find all Characters in a moonlit room with a certain level of `lycanthrophy` - we decide that if they have been _newly bitten_, they should also turn, _regardless_ of their lycanthropy level (more dramatic that way!).
 
 Let's say that getting bitten means that you'll get assigned a Tag `recently_bitten`.
 
@@ -242,7 +242,7 @@ will_transform = (
     .filter(
         Q(db_location__db_tags__db_key__iexact="moonlit")
         & (
-          Q(db_attributes__db_key="lycantrophy",
+          Q(db_attributes__db_key="lycanthropy",
             db_attributes__db_value__eq=2)
           | Q(db_tags__db_key__iexact="recently_bitten")
         ))
@@ -256,7 +256,7 @@ That's quite compact. It may be easier to see what's going on if written this wa
 from django.db.models import Q
 
 q_moonlit = Q(db_location__db_tags__db_key__iexact="moonlit")
-q_lycantropic = Q(db_attributes__db_key="lycantrophy", db_attributes__db_value__eq=2)
+q_lycantropic = Q(db_attributes__db_key="lycanthropy", db_attributes__db_value__eq=2)
 q_recently_bitten = Q(db_tags__db_key__iexact="recently_bitten")
 
 will_transform = (
@@ -276,7 +276,7 @@ the same object with different relations.
 ```
 
 This reads as "Find all Characters in a moonlit room that either has the
-Attribute `lycantrophy` higher than two, _or_ which has the Tag
+Attribute `lycanthropy` equal to two, _or_ which has the Tag
 `recently_bitten`". With an OR-query like this it's possible to find the same
 Character via different paths, so we add `.distinct()` at the end. This makes
 sure that there is only one instance of each Character in the result.
@@ -406,4 +406,4 @@ in a format like the following:
 
 ## Conclusions
 
-We have covered a lot of ground in this lesson and covered several more complex topics. Knowing how to query using Django is a powerful skill to have. 
\ No newline at end of file
+We have covered a lot of ground in this lesson and covered several more complex topics. Knowing how to query using Django is a powerful skill to have.