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Remove added backticks from regex

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John R. Supplee 2021-01-28 23:33:18 +02:00
parent 010a1d07d9
commit 6ba4da9711
2 changed files with 6 additions and 6 deletions
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8
client/components/main/globalSearch.js
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@ -190,10 +190,10 @@ BlazeComponent.extendComponent({
this.searching.set(true);
const reOperator1 = `/^((?<operator>[\p{Letter}\p{Mark}]+):|(?<abbrev>[#@]))(?<value>[\p{Letter}\p{Mark}]+)(\s+|$)/iu`;
const reOperator2 = `/^((?<operator>[\p{Letter}\p{Mark}]+):|(?<abbrev>[#@]))(?<quote>["']*)(?<value>.*?)\k<quote>(\s+|$)/iu`;
const reText = `/^(?<text>\S+)(\s+|$)/u`;
const reQuotedText = `/^(?<quote>["'])(?<text>[\w\p{L}]+)\k<quote>(\s+|$)/u`;
const reOperator1 = /^((?<operator>[\p{Letter}\p{Mark}]+):|(?<abbrev>[#@]))(?<value>[\p{Letter}\p{Mark}]+)(\s+|$)/iu;
const reOperator2 = /^((?<operator>[\p{Letter}\p{Mark}]+):|(?<abbrev>[#@]))(?<quote>["']*)(?<value>.*?)\k<quote>(\s+|$)/iu;
const reText = /^(?<text>\S+)(\s+|$)/u;
const reQuotedText = /^(?<quote>["'])(?<text>[\w\p{L}]+)\k<quote>(\s+|$)/u;
const operators = {
'operator-board': 'boards',