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81 lines
2.5 KiB
Ruby
81 lines
2.5 KiB
Ruby
module RecurringTodos
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class WeeklyRecurrencePattern < AbstractRecurrencePattern
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def initialize(user)
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super user
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end
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def every_x_week
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get :every_other1
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end
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{ monday: 1, tuesday: 2, wednesday: 3, thursday: 4, friday: 5, saturday: 6, sunday: 0 }.each do |day, number|
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define_method("on_#{day}") do
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on_xday number
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end
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end
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def on_xday(n)
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get(:every_day) && get(:every_day)[n, 1] != ' '
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end
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def recurrence_pattern
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if every_x_week > 1
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I18n.t("todos.recurrence.pattern.every_n", :n => every_x_week) + " " + I18n.t("common.weeks")
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else
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I18n.t('todos.recurrence.pattern.weekly')
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end
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end
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def validate
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super
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validate_not_blank(every_x_week, "Every other nth week may not be empty for weekly recurrence setting")
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something_set = %w{ sunday monday tuesday wednesday thursday friday saturday }.inject(false) { |set, day| set || self.send("on_#{day}") }
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errors[:base] << "You must specify at least one day on which the todo recurs" unless something_set
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end
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def get_next_date(previous)
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start = determine_start_date(previous)
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day = find_first_day_in_this_week(start)
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return day unless day == -1
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# we did not find anything this week, so check the nth next, starting from
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# sunday
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start = start + self.every_x_week.week - (start.wday()).days
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start = find_first_day_in_this_week(start)
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return start unless start == -1
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raise Exception.new, "unable to find next weekly date (#{self.every_day})"
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end
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private
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def determine_start_date(previous)
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if previous.nil?
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return self.start_from || Time.zone.now
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else
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start = previous + 1.day
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if start.wday() == 0
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# we went to a new week, go to the nth next week and find first match
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# that week. Note that we already went into the next week, so -1
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start += (every_x_week - 1).week
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end
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unless self.start_from.nil?
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# check if the start_from date is later than previous. If so, use
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# start_from as start to search for next date
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start = self.start_from if self.start_from > previous
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end
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return start
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end
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end
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def find_first_day_in_this_week(start)
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# check if there are any days left this week for the next todo
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start.wday().upto 6 do |i|
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return start + (i - start.wday()).days if on_xday(i)
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end
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-1
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end
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end
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end
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