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add str2int
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1 changed files with 58 additions and 0 deletions
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@ -2755,3 +2755,61 @@ def int2str(number, adjective=False):
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if adjective:
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return _INT2STR_MAP_ADJ.get(number, f"{number}th")
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return _INT2STR_MAP_NOUN.get(number, str(number))
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_STR2INT_MAP = {
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"one": 1, "two": 2, "three": 3,
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"four": 4, "five": 5, "six": 6,
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"seven": 7, "eight": 8, "nine": 9,
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"ten": 10, "eleven": 11, "twelve": 12,
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"thirteen": 13, "fourteen": 14, "fifteen": 15,
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"sixteen": 16, "seventeen": 17, "eighteen": 18,
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"nineteen": 19, "twenty": 20, "thirty": 30,
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"forty": 40, "fifty": 50, "sixty": 60,
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"seventy": 70, "eighty": 80, "ninety": 90,
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"hundred": 100, "thousand": 1000,
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}
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def str2int(number):
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"""
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Converts a string to an integer.
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Args:
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number (str): The string to convert. It can be a digit such as "1", or a number word such as "one".
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Returns:
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int: The string represented as an integer.
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"""
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number = str(number)
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try:
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# it's a digit already
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return int(number)
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except:
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pass
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if i := _STR2INT_MAP.get(number):
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# it's a single number, return it
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return i
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number = number.replace(" and "," ")
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# split number words by spaces, hyphens and commas, to accommodate multiple styles
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numbers = [ word.lower() for word in re.split(r'[-\s\,]',number) if word ]
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sums = []
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for word in numbers:
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# check if it's a known number-word
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if i := _STR2INT_MAP.get(word):
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if not len(sums):
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# initialize the list with the current value
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sums = [i]
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else:
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# if the previous number was smaller, it's a multiplier
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# e.g. the "two" in "two hundred"
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if sums[-1] < i:
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sums[-1] = sums[-1]*i
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# otherwise, it's added on, like the "five" in "twenty five"
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else:
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sums.append(i)
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else:
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else:
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# invalid number-word, return None to error
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return None
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return sum(sums)
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